Nguyễn Thị Ái Vân
Giới thiệu về bản thân
Trò chơi | Số bạn chọn |
Cướp cờ | 5 |
Kéo co | 9 |
Nhảy bao bố | 12 |
Bịt mắt bắt dê | 8 |
Ô ăn quan | 6 |
a/ \(\dfrac{1}{3}+\dfrac{3}{4}-\dfrac{5}{6}\) b/\(\dfrac{-2}{3}+\dfrac{6}{5}:\dfrac{2}{3}-\dfrac{2}{15}\) c/\(\dfrac{-3}{7}+\dfrac{5}{13}+\dfrac{-4}{7}\) d/\(\dfrac{12}{19}+\dfrac{-8}{13}-\dfrac{12}{19}+\dfrac{5}{-13}+2\)
= \(\dfrac{4}{12}+\dfrac{9}{12}-\dfrac{10}{12}\) = \(\dfrac{-2}{3}+\dfrac{9}{5}-\dfrac{2}{15}\) = \(\left(\dfrac{-3}{7}+\dfrac{-4}{7}\right)+\dfrac{5}{13}\) = \(\left[\dfrac{12}{19}+\left(-\dfrac{12}{9}\right)\right]+\left(\dfrac{-8}{13}+\dfrac{5}{-13}\right)+2\)
= \(\dfrac{13}{12}-\dfrac{10}{12}\) = \(\dfrac{-10}{15}+\dfrac{27}{15}-\dfrac{2}{15}\) = \(\left(-1\right)+\dfrac{5}{13}\) = \(0+\left(-1\right)+2\)
= \(\dfrac{13-10}{12}\) = \(\dfrac{-17}{15}-\dfrac{2}{15}\dfrac{ }{ }\) = \(\dfrac{-13}{13}+\dfrac{5}{13}\) = \(\left(-1\right)+2\)
= \(\dfrac{2}{12}=\dfrac{1}{6}\) = \(\dfrac{\left(-17\right)-2}{15}\) = \(\dfrac{\left(-13\right)+5}{13}\) = \(1\)
= \(\dfrac{19}{15}\) = \(\dfrac{-8}{13}\)