a) $\genfrac{}{}{0ex}{}{1}{2}-\left(x+\genfrac{}{}{0ex}{}{1}{3}\right)=\genfrac{}{}{0ex}{}{5}{6}$

$\Rightarrow x+\genfrac{}{}{0ex}{}{1}{3}=\genfrac{}{}{0ex}{}{1}{2}-\genfrac{}{}{0ex}{}{5}{6}$

$\Rightarrow x+\genfrac{}{}{0ex}{}{1}{3}=\genfrac{}{}{0ex}{}{3}{6}-\genfrac{}{}{0ex}{}{5}{6}$

$\Rightarrow x+\genfrac{}{}{0ex}{}{1}{3}=-\genfrac{}{}{0ex}{}{2}{6}$

$\Rightarrow x=-\genfrac{}{}{0ex}{}{2}{6}-\genfrac{}{}{0ex}{}{1}{3}$

$\Rightarrow x=-\genfrac{}{}{0ex}{}{2}{3}$
 

jtedkfjadklfjeiojiowjeifjslkgjklfdnbdnbmvn,mbnlernhtiorwgksdtioejklfjkldsjtio4wjetkljklfjgisrtilrjkltgfdskljgoieruiltjgfkljgioejtklgjrfklgjioerjkljfgjreigjkdlfjgl

rektrktlgdskl;fkds;fk;lefkl;ksel;gjfkjgldgvm,.cviorjglkrlwgiwioruitgjksldjfklejtiowrefjklwej