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x.3,7+x.6,3=120b,x.3,7+x.6,3=120
x(3,7+6,3)=120x(3,7+6,3)=120
10x=12010x=120
x=120:10x=120:10
x=12(tm)
(15×24-x):0.25=100 : 1/4
(15×24-x):0.25 = 400
(15x24-x) = 100
360-x =100
x=260
(8.75+1.25 +5+1) x X=20
16 x X=20
X=20 :16
X=1.25

\(\frac{1}{2}+\frac{5}{6}\div5-\frac{3}{16}\left(-2\right)^2\)
\(=\frac{1}{2}+\frac{5}{6}\times\frac{1}{5}-\frac{3}{16}.4\)
\(=\frac{3}{6}+\frac{1}{6}-\frac{12}{16}\)
\(=\frac{4}{6}-\frac{12}{16}\)
\(=\frac{32}{48}-\frac{36}{48}\)
\(=\frac{-4}{48}=\frac{-1}{12}\)
\(1,7\times2,3+1,7\times\left(-3,7\right)-0,17\div0,1\)
\(=1,7\times2,3+1,7\times\left(-3,7\right)-1,7\)
\(=1,7\times\left(2,3-3,7-1\right)\)
\(=1,7\times\left(-2,4\right)\)
\(=-4,08\)

a, \(\frac{2}{3}x+\frac{5}{6}x+\frac{1}{2}=\frac{-3}{4}\)
\(\Leftrightarrow\frac{3}{2}x=\frac{-5}{4}\)
\(\Leftrightarrow x=\frac{-5}{6}\)
b, \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
\(\Leftrightarrow\frac{3}{5}.\left(3x-\frac{37}{10}\right)=\frac{-57}{10}\)
\(\Leftrightarrow3x-\frac{37}{10}=\frac{-19}{2}\)
\(\Leftrightarrow3x=\frac{-29}{5}\)
\(\Leftrightarrow x=\frac{-29}{15}\)
a) \(\frac{2}{3}x+\frac{5}{6}x+\frac{1}{2}=-\frac{3}{4}\)
\(x\left(\frac{2}{3}+\frac{5}{6}\right)+\frac{1}{2}=-\frac{3}{4}\)
\(x\cdot\frac{3}{2}=\frac{-5}{4}\)
\(x=-\frac{5}{6}\)
\(\frac{2}{5}+\frac{3}{5}\left(3x-3,7\right)=-\frac{53}{10}\)
\(\frac{3}{5}\left(3x-\frac{37}{10}\right)=-\frac{57}{10}\)
\(3x-\frac{37}{10}=-\frac{19}{2}\)
\(3x=\frac{-29}{5}\)
\(x=\frac{-29}{15}\)

a) 2/3*x-3/2*x=5/12
x*(2/3-3/2)=5/12
x*(-5/6)=5/12
x=5/12:(-5/6)
x=-1/2
b)2/5+3/5*(3x-3,7)=-53/10
3/5*(3x-3,7)=(-53/10)-2/5=-57/10
(3x-3,7)=(-57/10):3/5=-19/2
3x=(-19/2)+3,7
3x=-29/5
x=(-29/5):3=-29/15
c) 7/9:(2+3/4*x)+5/9=23/27
7/9:(2+3/4*x)=8/27
2+3/4*x=21/8
3/4*x=5/8
x=5/6
k mình nha
a) 2/3.x-3/2.x=5/12
x.(2/3-3/2) =5/12
x.-5/6 =5/12
x =5/12:-5/6
x =1/2
b)2/5+3/5.(3x-3,7)=-53/10
3/5.(3x-3,7)=-53/10-2/5
3/5.(3x-3,7)=-57/10
3x-3,7 =-57/10:3/5
3x-3,7 =-19/2
3x =--19/2+3,7
3x =-29/5
x =-29/5:3
x =29/15
c)7/9:(2+3/4.x)+5/9=23/27
7/9:(2+3/4.x) =23/27-5/9
7/9:(2+3/4.x) =28/27
2+3/4.x =7/9:28/27
2+3/4.x =3/4
3/4.x =3/4-2
3/4.x =-5/4
x =-5/4:3/4
x =-5/3

a) \(A=1,7+\left|3,4-x\right|\ge1,7\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|3,4-x\right|=0\Rightarrow x=3,4\)
Vậy Min(A) = 1,7 khi x = 3,4
b) \(B=\left|x+2,8\right|-3,5\ge-3,5\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|x+2,8\right|=0\Rightarrow x=-2,8\)
Vậy Min(B) = -3,5 khi x = -2,8
c) \(C=3,7+\left|4,3-x\right|\ge3,7\left(\forall x\right)\)
Dấu "=" xảy ra khi: \(\left|4,3-x\right|=0\Rightarrow x=4,3\)
Vậy Min(C) = 3,7 khi x = 4,3

a: \(=\dfrac{\left(1.6-1.6\right)\cdot\left(2.29-0.76\right)}{1.6+2.53}\cdot\dfrac{3.06:7.5+3.4\cdot0.38}{19-2.6\cdot0.5}=0\)
b: \(=\dfrac{17.8\cdot9.4-7.8\cdot9}{3-0.3\cdot0.3}=\dfrac{97.12}{2.4}=\dfrac{607}{15}\)

a) \(x.\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\)
\(\Leftrightarrow x.\left(-\frac{5}{6}\right)=\frac{5}{12}\)
\(\Leftrightarrow x=-\frac{1}{2}\)
b) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(\Leftrightarrow2+\frac{3}{4}x=\frac{21}{8}\)
\(\Leftrightarrow\frac{3}{4}x=\frac{5}{8}\)
\(\Leftrightarrow x=\frac{5}{6}\)
c) \(\frac{3}{5}.\left(3x-3,7\right)=-\frac{57}{10}\)
\(\Leftrightarrow3x-3,7=-\frac{19}{2}\)
\(\Leftrightarrow3x=-\frac{29}{5}\)
\(\Leftrightarrow x=-\frac{29}{15}\)
x - 3,7 = 5,7
=> x = 5,7 + 3,7
=> x =9,4
Vậy x =9,4
x - 3,7 = 5,7
=> x = 5,7 + 3,7
=> x = 9,4