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Đặt \(A=\left(\frac{5}{12}+1\frac{4}{3}-0,25\right):\frac{5}{8}+0,75\)
\(A=\left(\frac{5}{12}+\frac{7}{3}-\frac{1}{4}\right):\frac{5}{8}+0,75\)
\(A=\left(\frac{5}{12}+\frac{28}{12}-\frac{3}{12}\right):\frac{5}{8}+\frac{15}{32}:\frac{5}{8}\)
\(A=\frac{5}{2}:\frac{5}{8}+\frac{15}{32}:\frac{5}{8}\)
\(A=\left(\frac{5}{2}+\frac{15}{32}\right):\frac{5}{8}\)
\(A=\frac{19}{4}\)
CÓ PHẢI = 63/20 ĐÚNG KO
NẾU ĐÚNG THÌ K HOẶC KB NHÉ! ! !

\(1\dfrac{3}{5}+0,25\cdot\dfrac{16}{15}-\dfrac{13}{15}\\ =\dfrac{8}{5}+\dfrac{1}{4}\cdot\dfrac{16}{15}-\dfrac{13}{15}\\ =\dfrac{8}{5}+\dfrac{4}{15}-\dfrac{13}{15}\\ =\dfrac{8}{5}-\dfrac{3}{5}\\ =1\)
\(1\dfrac{3}{5}\)+0,25 x \(\dfrac{16}{15}-\dfrac{13}{15}\)
=\(\dfrac{8}{5}+\dfrac{1}{4}\) x \(\dfrac{1}{5}\)
=\(\dfrac{8}{5}+\dfrac{1}{20}\)
=\(\dfrac{32}{20}+\dfrac{1}{20}\)
=\(\dfrac{33}{20}\)

Chú ý : 1 và 4/3 = 1 + 4/3 = 7/3
( 5/12 + 1+4/3 - 0 ,25 ) : 5/8 - 75%
= ( 5/12 + 7/3 - 1/4 ) . 8/5 - 3/4
= ( 5/12 + 28/12 - 3/12 ) . 8/5 - 3/4
= 30/12 . 8/5 - 3/4
= 4 - 3/4
= 16/4 - 3/4
= 13/4
=(5/12+7/3-1/4):5/8-3/4
=(5/12+28/12-1/4):5/8-3/4
=(33/12-1/4):5/8-3/4
=(33/12-3/12):5/8-3/4
=30/12:5/8-3/4
=5/2:5/8-3/4
=5/2x8/5-3/4
=4-3/4
=4/1-3/4
=16/4-3/4
=13/4

\(A=\left(27,54.\frac{11}{16}-3.405\right):3\)
\(A=\left(\frac{15147}{800}-3.405\right):3\)
\(A=\frac{12423}{800}:3\)
\(A=\frac{4141}{800}\)
\(B=\left(\frac{1}{6}+0,1+\frac{1}{5}\right):\left(\frac{1}{6}+0,1-\frac{1}{5}\right)\)
\(B=\frac{7}{15}:\frac{1}{15}\)
\(B=7\)
\(C=\left(0,5-\frac{1}{3}+0,25\right):\left(0,25-\frac{1}{6}\right)\)
\(C=\frac{5}{12}:\frac{1}{12}\)
\(C=5\)
\(D=\frac{13,5.1420+4,5.780.3}{3+6+9+...+24+27}\)
Số số hạng từ 3 đến 27 là:
(27-3):3+1=9(số hạng)
Tổng dãy số từ 3 đến 27 là:
(27+3)x9:2=135
\(D=\frac{13,5.1420+13,5.780}{135}\)
\(D=\frac{13,5.\left(1420+780\right)}{135}\)
\(D=2200\)

a) \(\dfrac{9}{8}+\dfrac{3}{8}:x=0,25\\ < =>\dfrac{9}{8}+\dfrac{3}{8}:x=\dfrac{1}{4}\\ =>\dfrac{3}{8}:x=\dfrac{1}{4}-\dfrac{9}{8}=-\dfrac{7}{8}\\ =>x=\dfrac{\dfrac{3}{8}}{-\dfrac{7}{8}}=-\dfrac{3}{7}\)
b) \(\left(\dfrac{2x}{5}-1\right):\left(-5\right)=\dfrac{1}{7}\\ =>\dfrac{2x}{5}-1=\dfrac{1}{7}.\left(-5\right)=-\dfrac{5}{7}\\ =>\dfrac{2x}{5}=-\dfrac{5}{7}+1=\dfrac{2}{7}\\ =>2x=\dfrac{2}{7}.5=\dfrac{10}{7}\\ =>x=\dfrac{\dfrac{10}{7}}{2}=\dfrac{5}{7}\)

\(\dfrac{1}{5}.\left(\dfrac{-7}{3}+\dfrac{2}{8}\right):0,25\)
\(=\dfrac{1}{5}.\left(\dfrac{-56}{24}+\dfrac{6}{24}\right):\dfrac{1}{4}\)
\(=\dfrac{1}{5}.\dfrac{-25}{12}:\dfrac{1}{4}\)
\(=\dfrac{-5}{12}:\dfrac{1}{4}\)
\(=\dfrac{-5}{3}\)

= \(\left(\dfrac{25}{100}+\dfrac{3}{5}-\dfrac{75}{100}+\dfrac{7}{5}\right):\dfrac{-5}{2}\)
= \(\left(\dfrac{25}{100}+\dfrac{3}{5}_{ }+\dfrac{-75}{100}+\dfrac{7}{5}\right).\dfrac{-2}{5}\)
= \(\left(\dfrac{1}{4}+\dfrac{3}{5}+\dfrac{-3}{4}+\dfrac{7}{5}\right).\dfrac{-2}{5}\)
= \(\left[\left(\dfrac{1}{4}+\dfrac{-3}{4}\right)+\left(\dfrac{3}{5}+\dfrac{7}{5}\right)\right].\dfrac{-2}{5}\)
= \(\left(\dfrac{-2}{4}+\dfrac{10}{5}\right).\dfrac{-2}{5}\)
= \(\left(\dfrac{-10}{20}+\dfrac{40}{20}\right).\dfrac{-2}{5}\)
= \(\dfrac{30}{20}.\dfrac{2}{5}\)
= \(\dfrac{30.2}{20.5}\)
= \(\dfrac{6.1}{10.1}\)
= \(\dfrac{6}{10}=\dfrac{3}{5}\)
= (25100+35−75100+75):−52(25100+35−75100+75):−52
= (25100+35+−75100+75).−25(25100+35+−75100+75).−25
= (14+35+−34+75).−25(14+35+−34+75).−25
= [(14+−34)+(35+75)].−25[(14+−34)+(35+75)].−25
= (−24+105).−25(−24+105).−25
= (−1020+4020).−25(−1020+4020).−25
= 3020.253020.25
= 30.220.530.220.5
= 6.110.16.110.1
= 610=35

\(-2\frac{3}{8}+0,25-40\%\cdot\frac{5}{24}\)
\(=-2\frac{3}{8}+0,25-\frac{1}{2}\)
\(=-2\frac{3}{8}+\frac{1}{4}-\frac{1}{12}\)
\(=-\frac{17}{8}-\frac{1}{12}\)
\(=-\frac{53}{24}=-2\frac{5}{24}\)
\(5\cdot\left(-0,25\right)+9\cdot0,75\)
=-1,25+6,75
=5,5
(−0,25)+9×0,75
\(= - 0 , 25 + 6 , 75\)
\(= 6 , 5\)