Tìm x, biết :
| x + \(\frac{4}{15}\)| - | -375 | = -| -2,15 |
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|x+4/15|-|-375|=-|-2,15|
|x+4/15|-375=-2,15
|x+4/15|=(-2,15)+375
|x+4/15|=372,85
<=> x+4/15=372,85 hoặc x+4/15=-372,85
<=>x=4471/12 hoặc x=-22387/60
Vậy x € { 4471/12 ; -22387/60 }
\(\left|x+\frac{4}{15}\right|-375=\) \(-2,15\)
<=>\(\left|x+\frac{4}{15}\right|=372,85\)
<=> \(\hept{\begin{cases}x+\frac{4}{15}=372,85\\x+\frac{4}{15}=-372,85\end{cases}}\)
<=> \(\hept{\begin{cases}x=\frac{4471}{12}\\x=\frac{-22387}{60}\end{cases}}\)
/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
/x + \(\frac{4}{15}\)/ - 3,75 = -2,15
=> /x + \(\frac{4}{15}\)/ = 1,6
=> \(x+\frac{4}{5}=1,6\) hoặc \(x+\frac{4}{5}=-1,6\)
=> \(x=0,8\)hoặc \(x=-2,4\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
Ta có 2 trường hợp
trường hợp 1
\(x+\frac{4}{15}=1,6\)
\(x=1,6-\frac{4}{15}\)
\(x=\frac{4}{3}\)
Trường hợp 2
\(x+\frac{4}{15}=-1,6\)
\(x=-1,6-\frac{4}{15}\)
\(x=\frac{-28}{15}\)
Vậy \(x=\left\{-\frac{28}{15};\frac{4}{3}\right\}\)
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
làm tiếp cái trước(ấn nhầm)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=\frac{5.4}{6.4.7}-\frac{15.6}{4.7.6}\)
\(x=\frac{20}{168}-\frac{90}{168}\)
\(x=\frac{-70}{168}\)
\(x=\frac{-5}{12}\)
2.
1.
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)
\(\frac{11}{13}-\frac{11}{13}-\frac{5}{42}+\frac{15}{28}=-x\)