11,13,15 ạ mong đc giúp ạ.Em cần gấp ạ
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\(\dfrac{-15}{2}=\dfrac{-3}{\left|-4x+5\right|}\)
\(\Leftrightarrow\left|4x-5\right|=\dfrac{6}{15}=\dfrac{2}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-5=\dfrac{2}{5}\\4x-5=-\dfrac{2}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=\dfrac{27}{5}\\4x=\dfrac{23}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{27}{20}\\x=\dfrac{23}{20}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Em tách ra 1-2 bài/1 câu hỏi để mọi người hỗ trợ nhanh nhất nha!
Bài 3:
a: Ta có: \(B=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{\sqrt{x}}{x-1}\right):\left(\dfrac{2}{x}-\dfrac{2-x}{x\left(\sqrt{x}+1\right)}\right)\)
\(=\dfrac{x+2\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}:\dfrac{2\sqrt{x}+2-2+x}{x\left(\sqrt{x}+1\right)}\)
\(=\dfrac{x}{\sqrt{x}-1}\)
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\(Ba\rightarrow Ba^{2+}+2e\\ K\rightarrow K^++e\\ O+2e\rightarrow O^{2-}\\ N\rightarrow N^{5+}+5e\)
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