Tìm x,y biết :
a) 128 - 3( x + 4 ) = 23
b) [ ( 4x + 28 ) . 3 + 55 ] : 5 = 35
c) ( 12x - 43 ) . 83 = 4 . 84
d) 720 : [ 4 - ( 2x - 5 ) ] = 23 . 5
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\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)
c) \(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-64=4.8^4:8^3\)
\(12x-64=32\)
\(12x=32+64\)
\(12x=96\)
\(x=\dfrac{96}{12}\)
\(x=8\)
d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)
\(720:\left(41-2x+5\right):5=35\)
\(720:\left(46-2x\right)=35.5\)
\(720:\left(46-2x\right)=175\)
\(46-2x=720:175\)
\(46-2x=\dfrac{144}{35}\)
\(2x=46-\dfrac{144}{35}\)
\(2x=\dfrac{1466}{35}\)
\(x=\dfrac{1466}{35}:2\)
\(x=\dfrac{733}{35}\)
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
a,
128-3x-12=23
3x=128-12-23
3x=93
x=93:3
= 31
b,
(12x+84+55):5=35
12x+84+55=35.5
12x+84+55=175
12x=175-55-84
12x=36
x=36:12
x=3
128-3.(x+4) =23
3.(x+4) =128-23
3.(x+4) = 105
x+4 =105:3
x+4 =35
x = 35-4
x=31
a) -(-27-y)=18-(-7)
27+y=18+7
27+y=25
y=25-17
y=-2
b) -(-y-28)-(-11+5)=(-13)-28
y+28+11-5=-41
y+39=-41+5
y=-36-39
y=-75
c) y-(25+37)-(13+26)=-(-42)-142
y-62-39=42-142
y-101=-100
y=-100+101
y=1
d) -(-315-y)-(-122)=-(-25-125)
315+y+122=25+125
437+y=150
y=150-437
y=-287
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
a: =>3(x+4)=115
=>x+4=115/3
hay x=103/3
b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)
\(\Leftrightarrow12x-64=32\)
=>12x=96
hay x=8
c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)
=>(4x+28)x23=120
=>4x+28=120/23
=>4x=-524/23
hay x=-131/23
a) 128-3(x+4)=23
3(x+4)=128-23
3(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
b) [(4x+28).3+55]:5=35
(4x+28).3+55=35.5
(4x+28).3+55=175
(4x+28).3=175-55
(4x+28).3=120
4x+28=120:3
4x+28=40
4x=40+28
4x=68
x=68:4
x=17
c) ( 12x - 43 ) . 83 = 4 . 84
12x-64=4.(84:83)
12x-64=4.8
12x-64=32
12x=32+64
12x=96
x=96:12
x=8
d) 720 : [ 4 - ( 2x - 5 ) ] = 23 . 5
720:[4-(2x-5)] = 8.5
720:[4-(2x-5)]=40
4-(2x-5)=720:40
4-(2x-5)=18
2x-5=4-18
2x-5=-14
2x=-14+5
2x=-9
x=-9:2
x=\(\frac{-9}{2}\)