a, \(\dfrac{2x+3}{24}\) = \(\dfrac{3x-1}{32}\)
b, \(\dfrac{13x-2}{2x+5}\) = \(\dfrac{76}{17}\)
Đề bài là tìm x, mọi người giúp mình vs ạ
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a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\\ =>32\left(2x+3\right)=24\left(3x-1\right)\\ =>64x+96=72x-24\\ =>72x-64x=24+96\\ =>8x=120\\ =>x=120:8\\ =>x=15\)
b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\\=>76\left(2x+5\right)=17\left(13x-2\right)\\ =>152x+380=221x-34\\ =>221x-152x=34+380\\ =>69x=414\\ =>x=414:69\\ =>x=6\)
a.
\(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)
\(\Leftrightarrow\dfrac{4\left(2x+3\right)}{4.24}=\dfrac{3\left(3x-1\right)}{32.3}\)
\(\Leftrightarrow\dfrac{8x+12}{96}=\dfrac{9x-3}{96}\)
\(\Leftrightarrow8x+12=9x-3\)
\(\Leftrightarrow9x-8x=12+3\)
\(\Leftrightarrow x=15\)
b.
ĐKXĐ: \(x\ne-\dfrac{5}{2}\)
\(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Leftrightarrow\dfrac{17\left(13x-2\right)}{17\left(2x+5\right)}=\dfrac{76\left(2x+5\right)}{17\left(2x+5\right)}\)
\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)
\(\Leftrightarrow221x-34=152x+380\)
\(\Leftrightarrow69x=414\)
\(\Leftrightarrow x=6\)
-7/(1 + 2x) = 5(2 - 3x)
-7(2 - 3x) = 5(1 + 2x)
-14 + 21x = 5 + 10x
21x - 10x = 5 + 14
11x = 19
x = 19/11
=>7/-(1+2x)=5/2x-3
=>7/2x-1=5/2x-3
=>7.(2x-3)=5.(2x-1)
=>14x-21=10x-5
=>10x-(14x-21)=5
=>10x-14x+21=5
=>10x-14x=5-21
=>(-4)x=-16
=>x=4
" . "là nhân ,còn " / "là phân số
\(A=\left(\dfrac{2x+1}{2\left(x+2\right)}-\dfrac{x}{3\left(x-2\right)}-\dfrac{2x^2}{3\left(x-2\right)\left(x+2\right)}\right)\cdot\dfrac{24-12x}{13x+6}\)
\(=\dfrac{3\left(2x+1\right)\left(x-2\right)-2x\left(x+2\right)-4x^2}{6\left(x-2\right)\left(x+2\right)}\cdot\dfrac{12\left(2-x\right)}{13x+6}\)
\(=\dfrac{3\left(2x^2-3x-2\right)-2x^2-4x-4x^2}{x+2}\cdot\dfrac{-2}{13x+6}\)
\(=\dfrac{6x^2-9x-6-6x^2-4x}{x+2}\cdot\dfrac{-2}{13x+6}=\dfrac{2}{x+2}\)
1:
a: =>28x-8=9x+3
=>19x=11
=>x=11/19
b: =>(3x-1)(x-1)=(2x+1)(x+1)
=>3x^2-4x+1=2x^2+3x+1
=>x^2-7x=0
=>x=0 hoặc x=7
a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)
\(\Rightarrow32\left(2x+3\right)=24\left(3x-1\right)\)
\(\Rightarrow64x+96=72x-24\)
\(\Rightarrow8x=120\Rightarrow x=15\)
b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)
\(\Rightarrow221x-34=152x+380\)
\(\Rightarrow69x=414\Rightarrow x=6\)