\(\frac{25}{26}+\frac{1}{26}\)
K
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NK
5
YL
17 tháng 8 2017
Ta có: \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
<=> \(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}=\frac{9}{25}\)
<=> \(x+\frac{1}{5}=\frac{9}{25}\)và \(x+\frac{1}{5}=-\frac{9}{25}\)
=> x= \(\frac{4}{25}\) và x=\(-\frac{14}{25}\)
LL
2
IM
8 tháng 8 2016
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{2}{5}\\x=-\frac{4}{5}\end{array}\right.\)
4 tháng 5 2018
\(\left(x+\frac{1}{2}\right)\cdot\left(\frac{2}{3}-2x\right)=0\)
TH1 : \(\Rightarrow x+\frac{1}{2}=0\)
\(x=0-\frac{1}{2}\)
\(x=\frac{-1}{2}\)
TH2 : \(\Rightarrow\frac{2}{3}-2x=0\)
\(2x=0+\frac{2}{3}=\frac{2}{3}\)
\(x=\frac{2}{3}\div2=\frac{1}{3}\)
\(\Rightarrow x=\frac{-1}{2};\frac{1}{3}\)
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)
\(x=\frac{3}{5}^2-\frac{1}{5}^2\)
\(x=\frac{2}{5}\)
DQ
2
27 tháng 4 2015
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{3}{5}^2\)
\(\left(x+\frac{1}{5}\right)=\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{1}{5}\)
\(x=\frac{2}{5}\)
27 tháng 4 2015
(x+1/5) . (x+1/5)=26/25-17/25
x+1/5 .x+1/5=9/25
x+1/5.x=9/25-5/25
x+1/5 . x=4/25
x.(1/5+1)=4/25
x. 6/5=4/25
x=4/25:6/5
x=2/15
\(\frac{25}{26}+\frac{1}{26}=\frac{26}{26}=1\)
\(k\)\(mk\)\(nhoa\)
\(\frac{25}{26}+\frac{1}{26}=\frac{25+1}{26}=\frac{26}{26}=1\)