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a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)

=>\(\left[2\left(10-x\right)+51\right]:3=5\)

=>\(\left[2\left(10-x\right)+51\right]=15\)

=>\(2\left(10-x\right)=15-51=-36\)

=>10-x=-36/2=-18

=>\(x=10-\left(-18\right)=10+18=28\)

b: \(\left(x-12\right)-15=20-\left(17+x\right)\)

=>\(x-12-15=20-17-x\)

=>\(x-27=3-x\)

=>\(2x=30\)

=>\(x=\dfrac{30}{2}=15\)

c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

=>\(720-\left[41-2x+5\right]=8\cdot5=40\)

=>\(\left[41-2x+5\right]=720-40=680\)

=>-2x+46=680

=>-2x=680-46=634

=>\(x=\dfrac{634}{-2}=-317\)

a: \(\left(15-x\right)+\left(x-12\right)=7-\left(x-5\right)\)

=>7-x+5=15-x+x-12

=>12-x=3

hay x=9

b: \(\Leftrightarrow x-\left\{57-\left[42-23-x\right]\right\}=13-\left\{47+25-32+x\right\}\)

\(\Leftrightarrow x-\left\{57-19+x\right\}=13-\left\{40+x\right\}\)

=>x-38-x=13-40-x

=>-27-x=-38

=>x+27=38

hay x=11

e: \(x^2+3x+9⋮x+3\)

\(\Leftrightarrow x\left(x+3\right)+9⋮x+3\)

\(\Leftrightarrow x+3\in\left\{1;-1;9;-9;3;-3\right\}\)

hay \(x\in\left\{-2;-4;6;-12;0;-6\right\}\)

 

4 tháng 2 2022

d) \(x-\left(-25+x\right)=13-x.\)

\(\Rightarrow x+25+x=13-x\)

\(\Rightarrow x+x+x=13-25\)

\(\Rightarrow3x=-12\)

\(\Rightarrow x=-4\)

e) \(15-\left(30+x\right)=x-\left(27-\text{| }-8\text{| }\right)\)

\(\Rightarrow15-30-x=x-19\)

\(\Rightarrow-15-x=x-19\)

\(\Rightarrow-15+19=x+x\)

\(\Rightarrow4=2x\)

\(x=2\)

f) \(\left(12x-4^3\right).8^3=4.8^4\)

\(\left(12x-2^6\right).2^9=2^2.2^{12}\)

\(12x-2^6=2^2.2^{12}\div2^9\)

\(12x-64=2^5=32\)

\(12x=96\)

\(x=8\)

g) \(\left[119-\left(3^3-10\right)\right].x=2448\)

\(\left[119-\left(27-10\right)\right].x=2448\)

\(\left[119-17\right].x=2448\)

\(102.x=2448\)

\(x=24\)

h) 

 [( 10 - x ) .2-51] : 3 - 2 = 3

    [( 10 - x ) .2-51] : 3      = 3 + 2

    [( 10 - x ) .2-51] : 3      = 5

     ( 10 - x ) .2 - 51          = 5 . 3

      ( 10 - x ) . 2 - 51        = 15 

    ( 10 - x ) . 2                 = 15 + 51 

       ( 10 - x ) . 2              = 66

         10 - x                     = 66 : 2 

       10 - x                       = 33

          x                           = 10 - 33

          x                           = -23 

i) 

(x-12)-15 = (20-7)-(18+x)                              

     x-12-15  = 20-7-18-x                                                     

     x-27      =   -5-x                                                             

=> x-27+5+x = 0                                                       

          2x-25  =0

          2x = 0+25 = 25

k) 

4 tháng 2 2022

thank cậu

28 tháng 3 2020

#maianhhappy

28 tháng 3 2020

bài 1 tính giá trị biểu thức

( - 25 ) nhân ( -3 ) nhân x với x = 4

\(\left(-25\right).\left(-3\right).4\)

\(=\left(-25\right).4.\left(-3\right)\)

\(=-100.\left(-3\right)=300\)

( -1 ) nhân ( -4 ) nhân 5 nhân 8 nhân y với y =25

\(\left(-1\right).\left(-4\right).5.8.25\)

\(=4.5.8.25=4.25.5.8\)

\(=100.40=40000\)

( 2ab mũ 2 ) : c với a =4 ; b= -6 ; c =12

\(\left(2.4.\left(-6\right)\right)^2:12\)

\(=\left(-48\right)^2:12\)

\(=2304:12=192\)

[ ( -25 ) nhân ( - 27 ) nhân ( -x ) ] : y với x = 4 ; y = -9

\(\left[\left(-25\right).\left(-27\right).\left(-4\right)\right]:-9\)

\(=-2700:\left(-9\right)\)

\(=300\)

(a mũ 2 _ b mũ 2) : ( a + b ) nhân ( a _ b ) với a + 5 , b = -3

\(\left(5^2-\left(-3\right)^2\right):\left(5-3\right).\left(5+3\right)\)

\(=16:2.8\)

\(=8.8=64\)

5 tháng 2 2020

a, 43 + ( 9 - 21 ) = 317 - ( x + 317 )

   43 + ( -12 ) = 317 - x - 317

   43 - 12 = 317 - 317 - x

   -x = 31

   x = -31

b, (15-x) + (x-12) = 7- (-5 + x)

    15-x+x-12 = 7+5-x

     15-12 = 12-x

     3 = 12-x

     x =  12-3

     x = 9

c, x - { 57- [42+ (-23 - x)]} = 13- {47+ [25- (32-x)]}

   x - [57- (42-23-x)] = 13- [47+ (25-32+x)]

   x - [57- (19-x)] = 13- [47+ (x-7)]

   x - (57-19+x) = 13- (47+x-7)

   x - (38+x) = 13- (40+x)

   x-38-x = 13-40-x

   x = 13-40+38

   x = 11

28 tháng 2 2020

a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )

b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )

c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}

d , -7 + | x - 4 | = -3

4 tháng 2 2020

a) \(43+\left(9-21\right)=317-\left(x+317\right)\\ 43+9-21=317-x-317\\ 52-21=\left(317-317\right)-x\\ 31=-x\\ x=-31\)Vậy x = -31

b) \(\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\\ 15-x+x-12=7+5-x\\ \left(x-x\right)+\left(15-12\right)=12-x\\ 3=12-x\\ x=9\)Vậy x = 9

c) \(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\\ x-\left\{57-\left[42+\left(-23\right)-x\right]\right\}=13-\left\{47+\left[25-32+x\right]\right\}\\ x-\left\{57-42+23+x\right\}=13-\left\{47+25-32+x\right\}\\ x-57+42-23-x=13-47-25+32-x\\ -57+42-23=-34-25+32-x\\ -15-23=-59+32-x\\ -38=-27-x\\ x=11\)Vậy x = 11

d) \(-7+\left|x-4\right|=-3\\ \left|x-4\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\)Vậy \(x\in\left\{8;0\right\}\)

e) \(13-\left|x+5\right|=13\\ \left|x+5\right|=0\\ \Rightarrow x+5=0\\ \Rightarrow x=-5\)Vậy x = -5

g) \(\left|x-10\right|-\left(-12\right)=4\\ \left|x-10\right|=-8\\ \Rightarrow x\in\varnothing\left(\text{vì }\left|x-10\right|\ge0\text{với mọi }x\right)\)Vậy \(x\in\varnothing\)

h) \(\left|x+2\right|< 5\\ 0\le\left|x+2\right|< 5\\ \Rightarrow\left|x+2\right|\in\left\{1;2;3;4\right\}\\ \Rightarrow x+2\in\left\{1;-1;2;-2;3;-3;4;-4\right\}\\ \Rightarrow x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)Vậy \(x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)

5 tháng 2 2020

a) 43+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−3143+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−31Vậy x = -31

b) (15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9(15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9Vậy x = 9

c) x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11Vậy x = 11

d) −7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0−7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0Vậy x∈{8;0}x∈{8;0}

e) 13−|x+5|=13|x+5|=0⇒x+5=0⇒x=−513−|x+5|=13|x+5|=0⇒x+5=0⇒x=−5Vậy x = -5

g) |x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)|x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)Vậy x∈∅x∈∅

h) |x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}|x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}Vậy x∈{−1;−3;0;−4;1;−5;2;−6}

2 tháng 10 2018

a) 128 - 3(x + 4) = 23

             3(x + 4) = 128 -23

             3(x + 4) = 105

                x + 4  = 105 : 3

                x + 4  = 35

                x        = 35 - 4

                x        = 31

2 tháng 10 2018

\(a.128-3\left(x+4\right)=23.\)

\(3\left(x+4\right)=128-23\)

\(3\left(x+4\right)=105\)

\(x+4=105:3=35\)

\(x=35-4=31\)

\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)

\(\left(4x+28\right)\cdot3=175-55=120\)

\(4x+28=120:3=40\)

\(4x=40-28=12\)

\(x=12:4=3\)