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![](https://rs.olm.vn/images/avt/0.png?1311)
( 7 - \(x\))3 + (11 - 7)2 = 141
(7 - \(x\))3 + 42 = 141
( 7 - \(x\))3 + 16 = 141
(7 - \(x\))3 = 141 - 16
( 7 - \(x\))3 = 125
(7 - \(x\))3 = 53
7 - \(x\) = 5
\(x\) = 7 - 5
\(x\) = 2
\(\left(7-x\right)^3+\left(11-7\right)^2=141\)
\(\left(7-x\right)^3+4^2=141\)
\(\left(7-x\right)^3+16=141\)
\(\left(7-x\right)^3=141-16\)
\(\left(7-x\right)^3=125\)
\(\left(7-x\right)=5^3\)
\(\Rightarrow7-x=5\)
\(x=7-5\)
\(x=2\)
\(\text{Vậy x=2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1
\(2.3^x-5=7\)
\(2.3^x\) \(=7-5\)
\(3^x\) \(=2:2\)
\(3^x\) \(=1\)
\(x\) \(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{x}{9}=\frac{8}{6}\Rightarrow x=\frac{8}{6}.9=\frac{4}{3}.9=12\)
b) \(\frac{12}{x}=\frac{6}{7}\Rightarrow x=12:\frac{6}{7}=12.\frac{7}{6}=14\)
c) \(5\frac{2}{3}:x=3\frac{2}{3}-2\frac{1}{2}\Rightarrow\frac{17}{3}:x=\left(3-2\right)+\left(\frac{2}{3}-\frac{1}{2}\right)\)
\(\Rightarrow\frac{17}{3}:x=1+\frac{1}{6}=\frac{7}{6}\Rightarrow x=\frac{17}{3}:\frac{7}{6}=\frac{17}{3}.\frac{6}{7}=\frac{34}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
dsa=sgt
a)..
b)...
c)...
d)...
e) ?x?=0 nếu x=0
?x?=1nếu x=1 hoặc -1
ngodinhnghi3 sao ko trả lời câu hỏi của mình zậy hả mà câu hỏi của mình đâu có câu e) đâu mà
![](https://rs.olm.vn/images/avt/0.png?1311)
a)210-5x=200
5x=210-200
5x=10
x=10:2
x=5
B)210-5(x-10)=200
5(x-10)=210-200
5(x-10)=10
x-10=10:5=2
x=2+10=12
c)450:[41-(2x-5)]=3 mũ 2 .5
450:[41+5-2x]=45
41+5-2x=450:45
41+5-2x=10
2x=36
x=18
D)210:x-10=20
210:x=20+10
210:x=30
x=210:30
x=7
E)(5x-39).7+3=80
(5x-39).7=77
5x-39=11
5x=50
x=10
F(2x+1):7=2 mũ 2 nhân 3 mũ 2
(2x+1):7=36
2x+1=252
2x=251
x=251/2
![](https://rs.olm.vn/images/avt/0.png?1311)
1a) x - 1/3 = 13/6
x = 13/6 + 1/3
x = 5/2
b) -7/5 - x = 13/7 : 13/7
-7/5 - x = 1
x = -7/5 - 1
x = -12/5
2) A = 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/2015.2016
A = 1 -1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/2015 - 1/2016
A = 1 - 1/2016
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 5 . 4x = 80
4x = 80 : 5
4x = 16
4x = 42
Vậy x = 2
b. 15 - |x| = 25
|x| = 15 - 25
|x| = -10
=> x rỗng vì giá trị tuyệt đối của một số phải là số nguyên dương
c. x2 - [62 - (82 - 9 . 7)3 - 7 . 5]3 - 5 . 3 = 13
x2 - [36 - (64 - 63)3 - 35]3 - 15 = 1
x2 - [36 - 13 - 35]3 - 15 = 1
x2 - [36 - 1 - 35]3 - 15 = 1
x2 - 03 - 15 = 1
x2 - 0 - 15 = 1
x2 - 0 = 1 + 15
x2 - 0 = 16
x2 = 16 + 0
x2 = 16
x2 = 42
Vậy x = 4
d. (x - 7)3 = 25 . 52 + 2 . 102
(x - 7)3 = 32 . 25 + 2 . 100
(x - 7)3 = 800 + 200
(x - 7)3 = 1000
(x - 7)3 = 103
x - 7 = 10
x = 10 + 7
x = 17
Vậy x = 17
b 15-|x|=25
|x|=15-25
|x|=-10
Suy ra x=-10 hoặc x=10
a: \(\Leftrightarrow5x=20\)
hay x=4
b: \(\Leftrightarrow x+7=24\)
hay x=17
1) \(5x-7=13\Rightarrow5x=13+7=20\Rightarrow x=20:5=4\)
2) \(\Rightarrow3\left(x+7\right)=95-23=72\)
\(\Rightarrow x+7=72:3=24\Rightarrow x=24-7=17\)
3) \(\Rightarrow2x+27=343\Rightarrow2x=343-27=316\Rightarrow x=316:2=158\)