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\(\frac{7}{8}\div\left(\frac{14}{3}+\frac{14}{4}\right)+\frac{10}{14}\)
\(=\frac{7}{8}\div\left(\frac{56}{12}+\frac{52}{12}\right)+\frac{10}{14}\)
\(=\frac{7}{8}\div\frac{108}{12}+\frac{10}{14}\)
\(=\frac{7}{8}\div9+\frac{5}{7}\)
\(=\frac{7}{8}\times\frac{1}{9}+\frac{5}{7}\)
\(=\frac{7}{72}+\frac{5}{7}\)
\(=\frac{49}{504}+\frac{360}{504}\)
\(=\frac{409}{504}\)
\(\frac{30}{42}\div\left(\frac{5}{7}-\frac{5}{21}\right)+\frac{6}{8}\)
\(=\frac{6}{7}\div\left(\frac{15}{21}-\frac{5}{21}\right)+\frac{3}{4}\)
\(=\frac{6}{7}\div\frac{10}{21}+\frac{3}{4}\)
\(=\frac{6}{7}\times\frac{21}{10}+\frac{3}{4}\)
\(=\frac{126}{70}+\frac{3}{4}\)
\(=\frac{504}{280}+\frac{210}{280}\)
\(=\frac{714}{280}\)
\(\left(6-\frac{14}{15}\right).\frac{50}{38}-\frac{8}{18}\)
\(=\left(\frac{90}{15}-\frac{14}{15}\right).\frac{25}{19}-\frac{4}{9}\)
\(=\frac{76}{15}.\frac{25}{19}-\frac{4}{9}\)
\(=\frac{76.25}{15.19}-\frac{4}{9}\)
\(=\frac{19.2.2.5.5}{3.5.19}-\frac{4}{9}\)
\(=\frac{20}{3}-\frac{4}{9}\)
\(=\frac{60}{9}-\frac{4}{9}\)
\(=\frac{56}{9}\)
\(\frac{4}{6}+\frac{5}{21}.\left(\frac{4}{5}-\frac{2}{6}\right)\)
\(=\frac{2}{3}+\frac{5}{21}.\left(\frac{24}{30}-\frac{10}{30}\right)\)
\(=\frac{2}{3}+\frac{5}{21}.\frac{14}{30}\)
\(=\frac{2}{3}+\frac{70}{630}\)
\(=\frac{420}{630}+\frac{70}{630}\)
\(=\frac{490}{630}\)
\(=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)
\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)
\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)
\(=\frac{17}{33}\times\left(1-1\right)\)
\(=\frac{17}{33}\times0=\frac{17}{33}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a) {4\over12}={4.5\over12.5}={20\over60}\)
\({1\over5}={1.12\over5.12}={12\over60}\)
\({-4\over15}={-4.4\over15.5}={-16\over60}\)
b)\({-7\over10}={-7.3\over10.3}={-21\over20}\)
\({1\over2}={1.15\over2.15}={15\over30}\)
\({-4\over15}={-4.2\over15.2}={-8\over30}\)
c)\({-5\over14}={-5.30\over14.30}={-150\over420}\)
\({3\over20}={3.21\over20.21}={63\over420}\)
\({-4\over21}={-4.20\over21.20}={-80\over420}\)
d)\({4\over18}={4.5\over18.5}={20\over90}\)
\({1\over18}={1.18\over5.18}={18\over90}\)
\({-6\over15}={-6.6\over15.6}={-36\over90}\)
Nói lời giữ lời nha ^_^..........Mệt wá........
a)4/12=1.5/12.5=5/60
1/5=1.12/5.12=5/60
-4/15=-4.4/15.4=-16/60
b)-7/10=-7.3/10.3=-21/30
1/2=1.15/2.15=15/30
-4/15=-4.2/15.2=-8/30
c)-5/14=-5.30/14/30=150/420
3/20=3.21/20.21=63/420
-4/21=-4.20/21.20=-80/420
d)4/18=4.5/18.5=20/90
1/5=1.18/5.18=18/90
-6/15=-6.6/15.6=-36/90
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1
a) MC: 75
\(\frac{7}{-15}=\frac{-7}{15}=\frac{-7.5}{15.5}=\frac{-35}{75}\)
\(\frac{-8}{-25}=\frac{8}{25}=\frac{8.3}{25.3}=\frac{24}{75}\)
\(\frac{11}{-75}=\frac{-11}{75}\)
b) MC: 180
Cách làm tương tự
Bài 2:
\(\frac{-1}{8}=\frac{-3}{24}\)
\(\frac{2}{-3}=\frac{16}{-24}=\frac{-16}{24}\)
\(\frac{3}{-72}=\frac{1}{-24}=\frac{-1}{24}\)
\(\frac{5}{-6}=\frac{20}{-24}=\frac{-20}{24}\)
Bài 3:
\(1=\frac{16}{16}\)
\(\frac{5}{-8}=\frac{-10}{16}\)
\(0=\frac{0}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{3}{5}+\frac{-4}{15}=\frac{9}{15}-\frac{4}{15}=\frac{5}{15}=\frac{1}{3}\)
b, \(\frac{-1}{3}+\frac{2}{5}+\frac{2}{15}=\frac{-5}{15}+\frac{6}{15}+\frac{2}{15}=\frac{3}{15}=\frac{1}{5}\)
c, \(\frac{-3}{5}+\frac{7}{21}+\frac{-4}{5}+\frac{7}{5}=\frac{-3}{5}+\frac{1}{3}+\frac{-4}{5}+\frac{7}{5}=\left(\frac{-3}{5}+\frac{-4}{5}+\frac{7}{5}\right)+\frac{1}{3}=\frac{1}{3}\)
d, \(\frac{2}{7}+\frac{1}{9}+\frac{3}{7}+\frac{5}{9}+\frac{-5}{6}=\left(\frac{2}{7}+\frac{3}{7}\right)+\left(\frac{1}{9}+\frac{5}{9}\right)+\frac{-5}{6}=\frac{5}{7}+\frac{6}{9}+\frac{-5}{6}=\frac{90}{126}+\frac{84}{126}+\frac{-105}{126}=\frac{69}{126}=\frac{23}{42}\)
e, \(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}=\left(-1\right)+1+\frac{-1}{5}=\frac{-1}{5}\)
f, \(\frac{-3}{31}+\frac{-6}{17}+\frac{1}{25}+\frac{-28}{31}+\frac{-1}{17}+\frac{-1}{5}=\left(\frac{-3}{31}+\frac{-28}{31}\right)+\left(\frac{-6}{17}+\frac{-1}{17}\right)+\left(\frac{1}{25}+\frac{-1}{5}\right)=\left(-1\right)+\frac{-7}{17}+\frac{-4}{25}=\frac{-425}{425}+\frac{-175}{425}+\frac{-68}{425}=\frac{-668}{425}\)
Chúc bn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{3}{5}-\dfrac{3}{5}.\dfrac{2}{3}=\dfrac{3}{5}-\left(\dfrac{3}{5}.\dfrac{2}{3}\right)=\dfrac{3}{5}-\dfrac{2}{5}=\dfrac{1}{5}\)
b) \(\dfrac{-7}{9}.\dfrac{11}{15}-\dfrac{4}{15}.\dfrac{-7}{9}-\dfrac{7}{9}=\dfrac{-7}{9}.\left(\dfrac{11}{15}-\dfrac{4}{15}\right)-\dfrac{7}{9}=\dfrac{-7}{9}.\dfrac{7}{15}-\dfrac{7}{9}=-\dfrac{49}{135}-\dfrac{7}{9}=-\dfrac{154}{135}\)
d) \(3\dfrac{1}{7}-\left(4\dfrac{1}{2}+5\dfrac{3}{7}\right)=\dfrac{22}{7}-\left(\dfrac{9}{2}+\dfrac{38}{7}\right)=\dfrac{22}{7}-\left(\dfrac{63}{14}+\dfrac{76}{14}\right)=\dfrac{22}{7}-\dfrac{139}{14}=\dfrac{44}{14}-\dfrac{139}{14}=-\dfrac{95}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{4}{5}\); \(\dfrac{3}{4}\); \(\dfrac{11}{13}\)
b) \(\dfrac{25}{35}\); \(\dfrac{100}{140}\); \(\dfrac{85}{119}\)
a) Những phân số tối giản là: \(\dfrac{4}{5};\dfrac{3}{4};\dfrac{11}{13}\)
b) Những phân số bằng \(\dfrac{5}{7}\) là: \(\dfrac{25}{35};\dfrac{100}{140};\dfrac{16}{28};\dfrac{85}{119}\)
a) = ( 9/10 - 4/5) + ( 3/4 + 1/2)
= ( 9/10 - 8/10) + ( 3/4 + 2/4)
= 1/10 + 5/4
= 2/20 + 25/20 = 27/20
b) = (4/5 + 4/15) + (5/6 - 1/2)
= (12/15 - 4/15) + (5/6 - 3/6)
= 8/15 + 2/6
= 16/30 + 10/30
= 26/30 = 13/15
c) = 55 - 39 - 1 + 60 /75 = 75/75 = 1
d) = 47 + 35 - 36 + 15/42 = 61/42