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a) \(\dfrac{2}{3}=\dfrac{4}{6}\)
\(\dfrac{5}{6}=\dfrac{5}{6}\)
Do đó: \(\dfrac{2}{3}< \dfrac{5}{6}\)
mà \(\dfrac{5}{6}< 1< \dfrac{8}{7}\)
nên \(\dfrac{2}{3}< \dfrac{5}{6}< \dfrac{8}{7}\)
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\(\dfrac{1}{4}\),\(\dfrac{1}{2}\),\(\dfrac{75}{75}\),\(\dfrac{5}{3}\)
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a) \(\frac{3}{7};\frac{1}{3};\frac{1}{7}\)
b) \(\frac{7}{1};\frac{3}{1};\frac{7}{3}\)
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Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\) ; \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\) ; \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\)
\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\) ; \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)
⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)
1/2; 3/4; 5/6; 4/3
1/2;3/4;5/6;4/3