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a) \(\left(56\times27+56\times35\right)\div62=56\times\left(27+35\right)\div62=56\times62\div62=56\)
b) \(\frac{0,18\times1230+0,9\times4567\times2+3\times5310\times6}{1+4+7+10+....+52+55-514}\)
\(=\frac{0,18\times1230+\left(0,9\times2\right)\times4567+\left(3\times6\right)\times5310}{1+4+5+.....+52+55-514}\)
\(=\frac{0,18\times1230+0,18\times4567+0,18\times5310}{1+4+7+...+52+55-514}\)
\(=\frac{0,18\times\left(1230+4567+5310\right)}{\left(55+1\right)\times55\div2-514}\)
\(=\frac{0,18\times11107}{971}=\frac{1999,26}{971}\)
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a) \(\frac{25}{5}\); \(\frac{7}{3}\) ; \(\frac{25}{35}\); \(\frac{5}{8}\); \(\frac{21}{56}\)
b) \(\frac{9}{2}\) ; \(\frac{9}{7}\); \(\frac{25}{50}\); \(\frac{2}{9}\); \(\frac{1}{5}\)
k cho mk nha

\(\dfrac{x}{5}\) = \(\dfrac{48}{60}\)
\(x\) = \(\dfrac{48}{60}\) \(\times\) 5
\(x\) = 4
\(\dfrac{x}{7}\) = \(\dfrac{16}{56}\)
\(x\) = \(\dfrac{16}{56}\) \(\times\) 7
\(x\) = 2
\(\dfrac{8}{x}\) = \(\dfrac{72}{108}\)
\(x\) = 8 : \(\dfrac{72}{108}\)
\(x\) = 12
\(x\) - \(\dfrac{3}{12}\) = \(\dfrac{35}{84}\)
\(x\) = \(\dfrac{35}{84}\) + \(\dfrac{3}{12}\)
\(x\) = \(\dfrac{2}{3}\)



\(\frac{16}{3}:\frac{8}{3}=\frac{16}{3}\times\frac{3}{8}=\frac{16}{8}=2\)
\(\frac{63}{35}:\frac{21}{5}=\frac{63}{35}.\frac{5}{21}=\frac{3}{7}.\frac{1}{1}=\frac{3}{7}\)
\(\frac{8}{14}\times\frac{7}{8}=\frac{7}{14}=\frac{1}{2}\)
\(\frac{19}{14}\times\frac{7}{15}=\frac{19}{2}\times\frac{1}{15}=\frac{19}{30}\)
\(a,\frac{16}{3}:\frac{8}{3}=\frac{16}{3}\times\frac{3}{8}=\frac{8\times2\times3}{3\times8}=2\)
\(b,\frac{63}{35}:\frac{21}{5}=\frac{63}{35}\times\frac{5}{21}=\frac{21\times3\times5}{5\times7\times21}=\frac{3}{7}\)
\(c,\frac{8}{14}\times\frac{7}{8}=\frac{8\times7}{7\times2\times8}=\frac{1}{2}\)
\(d,\frac{19}{14}\times\frac{7}{15}=\frac{19\times7}{7\times2\times15}=\frac{19}{30}\)
Học tốt

a) x+ \(\frac{4}{5}\)= \(\frac{4}{5}\)+ ( \(\frac{3}{7}\)+ \(\frac{3}{5}\))
x + \(\frac{4}{5}\)= \(\frac{4}{5}\)+ \(\frac{36}{35}\)
=> x = \(\frac{36}{35}\)
Vậy : x = \(\frac{36}{35}\)
b) \(\frac{4}{9}\)+\(\frac{8}{9}\)+ \(\frac{12}{9}\)+ ... + \(\frac{56}{9}\)
= \(\frac{4+8+12+...+56}{9}\)
Ta có : 4+8+12 + ... +56
Số các số hạng của dẫy số trên là : ( 56 -4) + 4 +1 = 14 ( số hạng )
=> Tổng trên = ( 4+56) x 14 : 2 = 420
=> \(\frac{4}{9}\)+ \(\frac{8}{9}\)+ ... + \(\frac{56}{9}\)= \(\frac{420}{9}\)= \(\frac{140}{3}\)
a)x=3/7+3/5=3x(1/7+1/5)=36/35
b)=(4+8+...+56)/9=(56+4)x14/9=280/3
\(x+\dfrac{35}{56}=\dfrac{7}{8}\)
=>\(x+\dfrac{5}{8}=\dfrac{7}{8}\)
=>\(x=\dfrac{7}{8}-\dfrac{5}{8}=\dfrac{2}{8}=\dfrac{1}{4}\)
x=7/8-35/56
x=49/56-35/56
x=15/56